Copper Tube Heat Losses
Estimate radial heat transfer from actual tube dimensions, insulation and surface conditions. A pipe size and temperature difference alone are insufficient.
Source review: September 8, 2026
Identify the actual inside and outside diameters, length, pipe material and insulation thickness. Nominal size is a designation, not a substitute for measured or manufacturer-specified dimensions. Select thermal conductivities appropriate to each material and temperature.
The internal fluid and surrounding air each exchange heat with a surface. Their convection coefficients depend on the flow and geometry; they are inputs to this model. Outdoor wind, surface radiation and a changing fluid temperature can materially change the answer.
Use the pipe heat-transfer calculator for a uniform segment with specified conditions. It accepts copper or other pipe materials through the conductivity input.
Let Di and Do be the actual pipe diameters, t the radial insulation thickness and L the length. The exposed diameter is Ds = Do + 2t. Use metres, conductivities kp and ki in W/(m·K), and convection coefficients hi and ho in W/(m²·K).
- Inside convection: Ri = 1/(hi π Di L).
- Pipe conduction: Rp = ln(Do/Di)/(2Ï€ kp L).
- Insulation conduction: Rins = ln(Ds/Do)/(2Ï€ ki L).
- Outside convection: Ro = 1/(ho π Ds L).
The sum is Rtotal in K/W. Heat transfer is Q = (Tfluid − Tambient)/Rtotal, positive outward. A colder fluid produces a negative value, indicating heat gain. The heat rate per metre is Q/L. Across each resistance, the temperature drop is Q times that resistance.
The DOE heat-transfer handbook develops cylindrical conduction and combined conduction/convection. This calculation assumes steady radial flow, constant properties, perfect contact and uniform bulk temperatures. It excludes radiation and axial heat flow.
Constructed teaching case: inside diameter 20 mm, outside diameter 22 mm, insulation thickness 20 mm, pipe conductivity 380 W/(m·K), insulation conductivity 0.040 W/(m·K), inside coefficient 1000 W/(m²·K) and outside coefficient 10 W/(m²·K). Fluid is held at 60 °C and surrounding air at 20 °C. These chosen properties are not certified values for a copper grade or insulation product.
| Quantity | Result |
|---|---|
| Total thermal resistance | 0.4652 K/W |
| Heat transfer with insulation | 85.99 W (8.60 W/m) |
| Exposed insulation surface | 24.41 °C |
| Bare pipe with the same coefficients | 273.44 W |
| Reduction in heat-transfer magnitude | 187.46 W |
Change these assumptions and calculate your own case. Set thickness to zero for bare pipe. Enter temperatures in Kelvin: °C + 273.15.
Insulation adds conduction resistance but also increases the surface area exchanging heat with the surroundings. Consequently, a thin layer on a small cylinder can increase heat transfer under a fixed outside coefficient. Differentiating the insulation-plus-outside resistance with respect to outside radius gives a minimum resistance at r = ki/ho. This model result is not an economic optimum or a recommended insulation thickness.
The bare comparison keeps both convection coefficients unchanged. Real coefficients can change with diameter and surface temperature. Radiation requires a coupled surface energy balance; this calculator does not account for it by silently assigning a larger convection coefficient.
For a long pipe whose fluid cools significantly, divide the system into a suitable thermal model that updates fluid temperature along the flow. This constant-temperature segment is not an outlet-temperature calculation. Pipe supports, fittings, gaps, moisture and startup energy also need separate treatment.
A cold surface may require a condensation assessment using the ambient dew point, for which the humid-air calculator supplies a state estimate. That comparison alone does not model moisture transfer, vapour barriers or a compliant insulation assembly.