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By Luqman Ismat © 2025

Engineering API Solutions • Hydraulics Calculations • Thermal Systems • Pump Design

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Copper Tube Heat Losses

Estimate radial heat transfer from actual tube dimensions, insulation and surface conditions. A pipe size and temperature difference alone are insufficient.

Source review: September 8, 2026

Specify the boundary conditions

Identify the actual inside and outside diameters, length, pipe material and insulation thickness. Nominal size is a designation, not a substitute for measured or manufacturer-specified dimensions. Select thermal conductivities appropriate to each material and temperature.

The internal fluid and surrounding air each exchange heat with a surface. Their convection coefficients depend on the flow and geometry; they are inputs to this model. Outdoor wind, surface radiation and a changing fluid temperature can materially change the answer.

Use the pipe heat-transfer calculator for a uniform segment with specified conditions. It accepts copper or other pipe materials through the conductivity input.

Add cylindrical thermal resistances

Let Di and Do be the actual pipe diameters, t the radial insulation thickness and L the length. The exposed diameter is Ds = Do + 2t. Use metres, conductivities kp and ki in W/(m·K), and convection coefficients hi and ho in W/(m²·K).

  • Inside convection: Ri = 1/(hi Ï€ Di L).
  • Pipe conduction: Rp = ln(Do/Di)/(2Ï€ kp L).
  • Insulation conduction: Rins = ln(Ds/Do)/(2Ï€ ki L).
  • Outside convection: Ro = 1/(ho Ï€ Ds L).

The sum is Rtotal in K/W. Heat transfer is Q = (Tfluid − Tambient)/Rtotal, positive outward. A colder fluid produces a negative value, indicating heat gain. The heat rate per metre is Q/L. Across each resistance, the temperature drop is Q times that resistance.

The DOE heat-transfer handbook develops cylindrical conduction and combined conduction/convection. This calculation assumes steady radial flow, constant properties, perfect contact and uniform bulk temperatures. It excludes radiation and axial heat flow.

Worked example: an insulated 10-metre segment

Constructed teaching case: inside diameter 20 mm, outside diameter 22 mm, insulation thickness 20 mm, pipe conductivity 380 W/(m·K), insulation conductivity 0.040 W/(m·K), inside coefficient 1000 W/(m²·K) and outside coefficient 10 W/(m²·K). Fluid is held at 60 °C and surrounding air at 20 °C. These chosen properties are not certified values for a copper grade or insulation product.

Calculated from the stated inputs; same defaults as the linked calculator
QuantityResult
Total thermal resistance0.4652 K/W
Heat transfer with insulation85.99 W (8.60 W/m)
Exposed insulation surface24.41 °C
Bare pipe with the same coefficients273.44 W
Reduction in heat-transfer magnitude187.46 W

Change these assumptions and calculate your own case. Set thickness to zero for bare pipe. Enter temperatures in Kelvin: °C + 273.15.

Interpret the comparison

Insulation adds conduction resistance but also increases the surface area exchanging heat with the surroundings. Consequently, a thin layer on a small cylinder can increase heat transfer under a fixed outside coefficient. Differentiating the insulation-plus-outside resistance with respect to outside radius gives a minimum resistance at r = ki/ho. This model result is not an economic optimum or a recommended insulation thickness.

The bare comparison keeps both convection coefficients unchanged. Real coefficients can change with diameter and surface temperature. Radiation requires a coupled surface energy balance; this calculator does not account for it by silently assigning a larger convection coefficient.

For a long pipe whose fluid cools significantly, divide the system into a suitable thermal model that updates fluid temperature along the flow. This constant-temperature segment is not an outlet-temperature calculation. Pipe supports, fittings, gaps, moisture and startup energy also need separate treatment.

A cold surface may require a condensation assessment using the ambient dew point, for which the humid-air calculator supplies a state estimate. That comparison alone does not model moisture transfer, vapour barriers or a compliant insulation assembly.

References

  • US DOE Fundamentals Handbook, Heat Transfer: cylindrical conduction pp. 11–17 and combined convection pp. 20–23Accessed 2026-09-08